Solve the problem.
-Evaluate

where $R$ is the parallelepiped enclosed by the planes $8 x + y - z = 1,8 x + y - z = 3 , - x + 2 y + z = - 2 , - x + 2 y + z = 5$ $x - y + 2 z = - 1 , x - y + 2 z = 6$
A) $\frac { 729 } { 44 }$
B) $\frac { 180 } { 11 }$
C) $\frac { 735 } { 44 }$
D) $\frac { 169 } { 11 }$

Question

Solve the problem.
-Evaluate

where $R$ is the parallelepiped enclosed by the planes $8 x + y - z = 1,8 x + y - z = 3 , - x + 2 y + z = - 2 , - x + 2 y + z = 5$ $x - y + 2 z = - 1 , x - y + 2 z = 6$
A) $\frac { 729 } { 44 }$ 
B) $\frac { 180 } { 11 }$ 
C) $\frac { 735 } { 44 }$ 
D) $\frac { 169 } { 11 }$

Quizplus · Accepted Answer

The Answer of Solve the problem.
-Evaluate

where $R$ is the parallelepiped enclosed by the planes $8 x + y - z = 1,8 x + y - z = 3 , - x + 2 y + z = - 2 , - x + 2 y + z = 5$ $x - y + 2 z = - 1 , x - y + 2 z = 6$
A) $\frac { 729 } { 44 }$ 
B) $\frac { 180 } { 11 }$ 
C) $\frac { 735 } { 44 }$ 
D) $\frac { 169 } { 11 }$

Solve the Problem RRR Is the Parallelepiped Enclosed by the Planes 8x+y−z=1,8x+y−z=3,−x+2y+z=−2,−x+2y+z=58 x + y - z = 1,8 x + y - z = 3 , - x + 2 y + z = - 2 , - x + 2 y + z = 58x+y−z=1,8x+y−z=3,−x+2y+z=−2,−x+2y+z=5

Solve the Problem $R$ Is the Parallelepiped Enclosed by the Planes $8 x + y - z = 1,8 x + y - z = 3 , - x + 2 y + z = - 2 , - x + 2 y + z = 5$