Find the limit.
-$$r ( t ) = ( 3 - 2 t ) \mathbf { i } + t j ; 0 \leq t \leq \frac { 3 } { 2 }$$
A) Figure 8
B) Figure 1
C) Figure 3
D) Figure 5

Question

Quizplus · Accepted Answer

The given function $r(t) = (3 - 2t) \mathbf{i} + tj$ describes a line segment in the plane, starting from the point (3,0) when $t=0$ and ending at the point (-3, 3/2) when $t=3/2$. This is a straight line, not any of the more complex shapes like a figure 8 or a figure 5. Therefore, the correct choice is the one that represents a simple line segment.

Find the Limit r(t)=(3−2t)i+tj;0≤t≤32r ( t ) = ( 3 - 2 t ) \mathbf { i } + t j ; 0 \leq t \leq \frac { 3 } { 2 }r(t)=(3−2t)i+tj;0≤t≤23​

Find the Limit $r ( t ) = ( 3 - 2 t ) \mathbf { i } + t j ; 0 \leq t \leq \frac { 3 } { 2 }$