Estimate the limit by graphing the function for an appropriate domain. Confirm your estimate by using L'Hopital's rule.
Show each step of your calculation.
-Which one is correct, and which one is wrong? Give reasons for your answers.
(a) $\lim _ { x \rightarrow 2 } \frac { x + 2 } { x ^ { 2 } - 4 } = \lim _ { x \rightarrow 2 } \frac { 1 } { 2 x } = - \frac { 1 } { 4 }$
(b)
$\lim _ { x \rightarrow 2 } \frac { x + 2 } { x ^ { 2 } - 4 } = \frac { 0 } { - 8 } = 0$

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The Answer of Estimate the limit by graphing the function for an appropriate domain. Confirm your estimate by using L'Hopital's rule.
Show each step of your calculation.
-Which one is correct, and which one is wrong? Give reasons for your answers.
(a) $\lim _ { x \rightarrow 2 } \frac { x + 2 } { x ^ { 2 } - 4 } = \lim _ { x \rightarrow 2 } \frac { 1 } { 2 x } = - \frac { 1 } { 4 }$
(b)
$\lim _ { x \rightarrow 2 } \frac { x + 2 } { x ^ { 2 } - 4 } = \frac { 0 } { - 8 } = 0$

Estimate the Limit by Graphing the Function for an Appropriate lim⁡x→2x+2x2−4=lim⁡x→212x=−14\lim _ { x \rightarrow 2 } \frac { x + 2 } { x ^ { 2 } - 4 } = \lim _ { x \rightarrow 2 } \frac { 1 } { 2 x } = - \frac { 1 } { 4 }limx→2​x2−4x+2​=limx→2​2x1​=−41​

Estimate the Limit by Graphing the Function for an Appropriate $\lim _ { x \rightarrow 2 } \frac { x + 2 } { x ^ { 2 } - 4 } = \lim _ { x \rightarrow 2 } \frac { 1 } { 2 x } = - \frac { 1 } { 4 }$