Solve the problem.
-A semicircular plate 18 ft in diameter sticks straight down into fresh water with the diameter along the surface. Find the force exerted by the water on one side of the plate.
A) 30,326.4 lb
B) 68,234.4 lb
C) 45,489.6 lb
D) 22,744.8 lb

Question

Quizplus · Accepted Answer

The force exerted by the water on one side of the plate is given by the formula F = (1/2)ρghA, where ρ is the density of water, g is the acceleration due to gravity, h is the depth of the water, and A is the area of the plate. In this case, the density of water is 62.4 lb/ft³, the acceleration due to gravity is 32 ft/s², the depth of the water is 9 ft, and the area of the plate is (1/2)πr² = (1/2)π(9)² = 81π ft². Plugging these values into the formula, we get F = (1/2)(62.4)(32)(81π) = 30,326.4 lb.

Solve the Problem. -A Semicircular Plate 18 Ft in Diameter Sticks Straight Down