Solve the problem.
-A spring has a natural length of 26 in. A force of 1600 lb stretches the spring to 36 in. How far beyond its natural length will a 400 lb force stretch the spring?
A) 2.5 in.
B) 40 in.
C) 5 in.
D) 4 in.

Question

Quizplus · Accepted Answer

The spring constant k can be found using Hooke's Law, F = kx, where F is the force applied, x is the displacement from the natural length, and k is the spring constant. With a force of 1600 lb stretching the spring 10 in. (from 26 in. to 36 in.), we find k = 1600/10 = 160 lb/in. For a 400 lb force, using F = kx again, 400 = 160x, solving for x gives x = 400/160 = 2.5 in. beyond its natural length.

Solve the Problem. -A Spring Has a Natural Length of 26 In. a 26