Solve the problem.
-It took 1900 J of work to stretch a spring from its natural length of 1 m to a length of 3 m. Find the spring's force constant.
A) 3800 N/m
B) 475 N/m
C) 950 N/m
D) 1425 N/m

Question

Quizplus · Accepted Answer

The work done to stretch a spring is given by the formula W = (1/2)kx^2, where W is the work done, k is the force constant, and x is the displacement of the spring from its natural length.

In this problem, we are given the work W as 1900 J and the displacement x as 3 m - 1 m = 2 m. Substituting these values into the formula, we get:

1900 J = (1/2)k(2 m)^2

Solving for k, we get:

k = (2 x 1900 J) / (2 m)^2 = 950 N/m

Therefore, the answer is C) 950 N/m.

Solve the Problem. -It Took 1900 J of Work to Stretch a Spring