Find the derivative of y with respect to the appropriate variable.
-$$y = 3 \ln x + \sqrt { 1 - x ^ { 2 } } \operatorname { sech } ^ { - 1 } x$$
A) $\frac { 2 } { x } - \frac { x \operatorname { sech } ^ { - 1 } x } { 2 \sqrt { 1 - x ^ { 2 } } }$
B) $\frac { 2 } { x } - \frac { x \operatorname { sech } ^ { - 1 } x } { \sqrt { 1 - x ^ { 2 } } }$
C) $3 \ln x - \operatorname { sech } ^ { - 1 } x$
D) $\frac { 3 } { x } - \frac { \operatorname { sech } ^ { - 1 } x } { \sqrt { 1 - x ^ { 2 } } }$

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The Answer of Find the derivative of y with respect to the appropriate variable.
-$$y = 3 \ln x + \sqrt { 1 - x ^ { 2 } } \operatorname { sech } ^ { - 1 } x$$
A) $\frac { 2 } { x } - \frac { x \operatorname { sech } ^ { - 1 } x } { 2 \sqrt { 1 - x ^ { 2 } } }$
B) $\frac { 2 } { x } - \frac { x \operatorname { sech } ^ { - 1 } x } { \sqrt { 1 - x ^ { 2 } } }$
C) $3 \ln x - \operatorname { sech } ^ { - 1 } x$
D) $\frac { 3 } { x } - \frac { \operatorname { sech } ^ { - 1 } x } { \sqrt { 1 - x ^ { 2 } } }$

Find the Derivative of Y with Respect to the Appropriate y=3ln⁡x+1−x2sech⁡−1xy = 3 \ln x + \sqrt { 1 - x ^ { 2 } } \operatorname { sech } ^ { - 1 } xy=3lnx+1−x2​sech−1x

Find the Derivative of Y with Respect to the Appropriate $y = 3 \ln x + \sqrt { 1 - x ^ { 2 } } \operatorname { sech } ^ { - 1 } x$