Solve the Problem $y = \frac { 7 } { \sqrt { 6 x + 1 } } , x = 0 , x = 3$

Solve the problem.
-Find the volume of the solid that is generated by revolving the area bounded by $y = \frac { 7 } { \sqrt { 6 x + 1 } } , x = 0 , x = 3$ , and $y = 0$ about the $x$ -axis.

A) $\frac { 7 } { 6 } \pi \ln ( 6 )$
B) $\frac { 49 } { 6 } \pi \ln ( 6 )$
C) $\frac { 7 \sqrt { 6 } } { 6 } \pi \ln ( 19 )$
D) $\frac { 49 } { 6 } \pi \ln ( 19 )$