Evaluate the improper integral or state that it is divergent.
-$$\int _ { 1 } ^ { \infty } \frac { 9 } { \left( 1 + x ^ { 2 } \right) \tan ^ { - 1 } x } d x$$
A) $\frac { 9 } { 2 } \left( 1 + \frac { \pi } { 2 } \right) ^ { 2 }$
B) $9 \ln 2$
C) $9 \ln \frac { \pi } { 2 }$
D) $9 \ln \left( 1 + \frac { \pi } { 2 } \right)$

Question

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The Answer of Evaluate the improper integral or state that it is divergent.
-$$\int _ { 1 } ^ { \infty } \frac { 9 } { \left( 1 + x ^ { 2 } \right) \tan ^ { - 1 } x } d x$$
A) $\frac { 9 } { 2 } \left( 1 + \frac { \pi } { 2 } \right) ^ { 2 }$
B) $9 \ln 2$
C) $9 \ln \frac { \pi } { 2 }$
D) $9 \ln \left( 1 + \frac { \pi } { 2 } \right)$

Evaluate the Improper Integral or State That It Is Divergent ∫1∞9(1+x2)tan⁡−1xdx\int _ { 1 } ^ { \infty } \frac { 9 } { \left( 1 + x ^ { 2 } \right) \tan ^ { - 1 } x } d x∫1∞​(1+x2)tan−1x9​dx

Evaluate the Improper Integral or State That It Is Divergent $\int _ { 1 } ^ { \infty } \frac { 9 } { \left( 1 + x ^ { 2 } \right) \tan ^ { - 1 } x } d x$