Find an equation of the secant line containing (1, f(1)) and (2, f(2)).
-$f ( x ) = \frac { 2 } { x + 1 }$
A) $y = \frac { 2 } { 3 } x + \frac { 1 } { 3 }$
B) $y = \frac { 1 } { 3 } x + \frac { 2 } { 3 }$
C) $y = \frac { 1 } { 3 } x + 2$
D) $y = - \frac { 1 } { 3 } x + \frac { 4 } { 3 }$

Question

Quizplus · Accepted Answer

To find the equation of the secant line, calculate the slope using the points (1, f(1)) and (2, f(2)). f(1) = 1 and f(2) = 2/3. The slope is (2/3 - 1)/(2 - 1) = -1/3. Using point-slope form with point (1, 1), the equation is y - 1 = -1/3(x - 1), which simplifies to y = -1/3x + 4/3.

Find an Equation of the Secant Line Containing (1, F(1)) f(x)=2x+1f ( x ) = \frac { 2 } { x + 1 }f(x)=x+12​

Find an Equation of the Secant Line Containing (1, F(1)) $f ( x ) = \frac { 2 } { x + 1 }$