Determine where the function is increasing and where it is decreasing.
-$$f ( x ) = x ^ { 2 } - 2 x$$
A) increasing on $( - \infty , - 1 )$
decreasing on $( - 1 , \infty )$
B) increasing on $( - \infty , 1 )$
decreasing on $( 1 , \infty )$
C) increasing on $( - 1 , \infty )$
decreasing on $( - \infty , - 1 )$
D) increasing on $( 1 , \infty )$
decreasing on $( - \infty , 1 )$

Question

Quizplus · Accepted Answer

To determine where the function is increasing or decreasing, we find its derivative: $f'(x) = 2x - 2$. Setting $f'(x) = 0$ gives $x = 1$. For $x < 1$, $f'(x) < 0$, so the function is decreasing. For $x > 1$, $f'(x) > 0$, so the function is increasing.

Determine Where the Function Is Increasing and Where It Is f(x)=x2−2xf ( x ) = x ^ { 2 } - 2 xf(x)=x2−2x

Determine Where the Function Is Increasing and Where It Is $f ( x ) = x ^ { 2 } - 2 x$