Solve f(x) = g(x). Find the points of intersection of the graphs of the two functions.
-f(x) = 6x + 7 $g ( x ) = x ^ { 2 }$
A) $x = - 1 , x = 7$
B) $x = - 1 , x = \frac { 1 } { 7 }$
C) $x = 1 , x = 7$
D) $x = 1 , x = - \frac { 1 } { 7 }$ $x = - 1 , x = 7$

Question

Solve f(x) = g(x). Find the points of intersection of the graphs of the two functions.
-f(x) = 6x + 7 $g ( x ) = x ^ { 2 }$ 
A) $x = - 1 , x = 7$
B) $x = - 1 , x = \frac { 1 } { 7 }$
C) $x = 1 , x = 7$
D) $x = 1 , x = - \frac { 1 } { 7 }$ $x = - 1 , x = 7$

Quizplus · Accepted Answer

To find the points of intersection, set $f(x) = g(x)$: $6x + 7 = x^2$. Rearrange to $x^2 - 6x - 7 = 0$. Factoring or using the quadratic formula yields $x = -1$ and $x = 7$.

Solve F(x) = G(x) g(x)=x2g ( x ) = x ^ { 2 }g(x)=x2

Solve F(x) = G(x) $g ( x ) = x ^ { 2 }$