Use factoring to find the zeros of the quadratic function. List the x-intercepts of the graph of the function.
-$$f ( x ) = x ^ { 2 } + 6 x - 16$$
A) x = 8, x = 2
B) x = 8, x = -2
C) x = -8, x = 1
D) x = -8, x = 2

Question

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To find the zeros of the quadratic function $f(x) = x^2 + 6x - 16$, we factor it. The factors of -16 that add up to 6 are 8 and -2. Thus, we can write the equation as $(x + 8)(x - 2) = 0$. Setting each factor equal to zero gives us the solutions $x = -8$ and $x = 2$, which are the x-intercepts of the graph.

Use Factoring to Find the Zeros of the Quadratic Function f(x)=x2+6x−16f ( x ) = x ^ { 2 } + 6 x - 16f(x)=x2+6x−16

Use Factoring to Find the Zeros of the Quadratic Function $f ( x ) = x ^ { 2 } + 6 x - 16$