Find $\lim _ { x \rightarrow \infty } \frac { 1 - 3 x } { 1 + 7 x }$ (if it exists).
A) 0
B) $- \frac { 3 } { 7 }$
C) $\frac { 3 } { 7 }$
D) $- \infty$
E) limit does not exist

Question

Quizplus · Accepted Answer

To find the limit as $x$ approaches infinity for the given function $\frac{1 - 3x}{1 + 7x}$, we can divide the numerator and the denominator by $x$, the highest power of $x$ in the expression. This simplifies to $\frac{\frac{1}{x} - 3}{\frac{1}{x} + 7}$. As $x$ approaches infinity, $\frac{1}{x}$ approaches 0, leaving us with $\frac{-3}{7}$, which is $-\frac{3}{7}$.

Find lim⁡x→∞1−3x1+7x\lim _ { x \rightarrow \infty } \frac { 1 - 3 x } { 1 + 7 x }limx→∞​1+7x1−3x​

Find $\lim _ { x \rightarrow \infty } \frac { 1 - 3 x } { 1 + 7 x }$