Find the magnitude of the vector $\mathbf { v }$ described below.
Initial point: $( 1 , - 8 , - 6 )$
Terminal point: $( - 9 , - 1 , - 6 )$
A) $- 29$
B) 17
C) $\sqrt { 17 }$
D) $2 \sqrt { 149 }$
E) $\sqrt { 149 }$

Question

Quizplus · Accepted Answer

The magnitude of a vector $\mathbf{v}$ from an initial point $(x_1, y_1, z_1)$ to a terminal point $(x_2, y_2, z_2)$ is given by $\sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2 + (z_2 - z_1)^2}$. Substituting the given points, we get $\sqrt{(-9 - 1)^2 + (-1 + 8)^2 + (-6 + 6)^2} = \sqrt{(-10)^2 + 7^2 + 0^2} = \sqrt{100 + 49} = \sqrt{149}$.

Find the Magnitude of the Vector v\mathbf { v }v Described Below

Find the Magnitude of the Vector $\mathbf { v }$ Described Below