Find the range of the quadratic function in interval notation.
-$$f ( x ) = 11 ( x - 3 ) ^ { 2 } + 8$$
A) $[ - 8 , \infty )$
B) $( - \infty , 8 ]$
C) $[ 8 , \infty )$
D) $[ 3 , \infty )$

Question

Quizplus · Accepted Answer

The given quadratic function is in vertex form, $f(x) = a(x - h)^2 + k$, where $a = 11$, $h = 3$, and $k = 8$. Since $a > 0$, the parabola opens upwards, and the vertex $(3, 8)$ represents the minimum point of the function. Therefore, the range is $[8, \infty)$.

Find the Range of the Quadratic Function in Interval Notation f(x)=11(x−3)2+8f ( x ) = 11 ( x - 3 ) ^ { 2 } + 8f(x)=11(x−3)2+8

Find the Range of the Quadratic Function in Interval Notation $f ( x ) = 11 ( x - 3 ) ^ { 2 } + 8$