-$\frac { 2 } { 3 } + \left( - \frac { 5 } { 9 } \right)$
A) $\frac { 11 } { 9 }$
B) $\frac { 1 } { 9 }$
C)$ = \frac { 1 } { 9 }$
D) $- \frac { 11 } { 9 }$

Question

-$\frac { 2 } { 3 } + \left( - \frac { 5 } { 9 } \right)$
A) $\frac { 11 } { 9 }$ 
B) $\frac { 1 } { 9 }$ 
C)$ = \frac { 1 } { 9 }$ 
D) $- \frac { 11 } { 9 }$

Quizplus · Accepted Answer

To add fractions, they must have a common denominator. The least common denominator of 3 and 9 is 9. Convert $\frac{2}{3}$ to $\frac{6}{9}$ so it has the same denominator as $\frac{-5}{9}$. Then, $\frac{6}{9} + \left(-\frac{5}{9}\right) = \frac{1}{9}$.

- 23+(−59)\frac { 2 } { 3 } + \left( - \frac { 5 } { 9 } \right)32​+(−95​)

- $\frac { 2 } { 3 } + \left( - \frac { 5 } { 9 } \right)$