Use intercepts and a checkpoint to graph the linear function.
-2x - 4y = 6
A) $\left( 0 , - \frac { 3 } { 2 } \right) , ( 3,0 )$
B) $\left( 0 , \frac { 3 } { 2 } \right) , ( - 3,0 )$
C) $\left( 0 , - \frac { 3 } { 2 } \right) , ( - 3,0 )$
D) $( 0,3 ) , \left( - \frac { 3 } { 2 } , 0 \right)$

Question

Use intercepts and a checkpoint to graph the linear function.
-2x - 4y = 6  
A) $\left( 0 , - \frac { 3 } { 2 } \right) , ( 3,0 )$ 
B) $\left( 0 , \frac { 3 } { 2 } \right) , ( - 3,0 )$ 
C) $\left( 0 , - \frac { 3 } { 2 } \right) , ( - 3,0 )$ 
D) $( 0,3 ) , \left( - \frac { 3 } { 2 } , 0 \right)$

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The Answer of Use intercepts and a checkpoint to graph the linear function.
-2x - 4y = 6  
A) $\left( 0 , - \frac { 3 } { 2 } \right) , ( 3,0 )$ 
B) $\left( 0 , \frac { 3 } { 2 } \right) , ( - 3,0 )$ 
C) $\left( 0 , - \frac { 3 } { 2 } \right) , ( - 3,0 )$ 
D) $( 0,3 ) , \left( - \frac { 3 } { 2 } , 0 \right)$

Use Intercepts and a Checkpoint to Graph the Linear Function (0,−32),(3,0)\left( 0 , - \frac { 3 } { 2 } \right) , ( 3,0 )(0,−23​),(3,0)

Use Intercepts and a Checkpoint to Graph the Linear Function $\left( 0 , - \frac { 3 } { 2 } \right) , ( 3,0 )$