Multiply using the rule for the product of the sum and difference of two terms. Assume any variable exponents represent whole numbers.
-$\left( y ^ { 3 } - 7 \right) \left( y ^ { 3 } + 7 \right)$
A) $y ^ { 6 } - 14$
B) $y ^ { 9 } - 49$
C) $y ^ { 9 } - 14$
D) $y ^ { 6 } - 49$

Question

Quizplus · Accepted Answer

The rule for the product of the sum and difference of two terms is $a^2 - b^2$ when multiplying $(a - b)(a + b)$. Applying this to the given expression, we get $y^6 - 49$, since $y^3$ squared is $y^6$ and $7$ squared is $49$.

Multiply Using the Rule for the Product of the Sum (y3−7)(y3+7)\left( y ^ { 3 } - 7 \right) \left( y ^ { 3 } + 7 \right)(y3−7)(y3+7)

Multiply Using the Rule for the Product of the Sum $\left( y ^ { 3 } - 7 \right) \left( y ^ { 3 } + 7 \right)$