Write the first four terms of the sequence whose general term is given.
-$$a _ { n } = \left( - \frac { 3 } { 4 } \right) ^ { n }$$
A) $- \frac { 3 } { 4 } , \frac { 9 } { 16 } , - \frac { 27 } { 64 } , \frac { 81 } { 256 }$
B) $- \frac { 3 } { 4 } , - \frac { 9 } { 16 } , - \frac { 27 } { 64 } , - \frac { 81 } { 256 }$
C) $\frac { 3 } { 4 } , - \frac { 3 } { 8 } , \frac { 3 } { 12 } , - \frac { 3 } { 16 }$
D) $- \frac { 3 } { 4 } , \frac { 3 } { 8 } , - \frac { 3 } { 12 } , - \frac { 3 } { 16 }$

Question

Quizplus · Accepted Answer

The sequence is generated by raising $-\frac{3}{4}$ to the power of $n$. For $n=1$, the term is $(-3/4)^1 = -3/4$. For $n=2$, it's $(-3/4)^2 = 9/16$. For $n=3$, it's $(-3/4)^3 = -27/64$. For $n=4$, it's $(-3/4)^4 = 81/256$. The sign alternates because of the negative base raised to successive powers.

Write the First Four Terms of the Sequence Whose General an=(−34)na _ { n } = \left( - \frac { 3 } { 4 } \right) ^ { n }an​=(−43​)n

Write the First Four Terms of the Sequence Whose General $a _ { n } = \left( - \frac { 3 } { 4 } \right) ^ { n }$