Find an equation of variation for the given situation.
-y varies directly as x and inversely as z , and y=4 when x=2 and z=6 .
A) $y = \frac { 11 z } { x }$
B) y=15 x z
C) $y = \frac { 12 x } { z }$
D) $y = \frac { 16 x } { z }$

Question

Find an equation of variation for the given situation.
-y varies directly as x and inversely as z , and  y=4  when  x=2  and  z=6 .
A) $y = \frac { 11 z } { x }$
B)  y=15 x z 
C) $y = \frac { 12 x } { z }$
D) $y = \frac { 16 x } { z }$

Quizplus · Accepted Answer

The equation for y varying directly as x and inversely as z is $y = k\frac{x}{z}$, where k is the constant of variation. Substituting the given values $y=4$, $x=2$, and $z=6$ into the equation gives $4 = k\frac{2}{6}$, solving for k gives $k=12$. Therefore, the correct equation is $y = \frac { 12 x } { z }$.

Find an Equation of Variation for the Given Situation y=11zxy = \frac { 11 z } { x }y=x11z​

Find an Equation of Variation for the Given Situation $y = \frac { 11 z } { x }$