Consider only the discriminant, $b ^ { 2 } - 4 a c$, to determine whether one real-number solution, two different real-number solutions, or two different imaginary-number solutions exist.
-$$x ^ { 2 } - 2 x - 6 = 0$$
A)Two different imaginary-number solutions
B)One real solution
C)Two different real-number solutions

Question

Quizplus · Accepted Answer

The discriminant for the equation $x^2 - 2x - 6 = 0$ is calculated as $b^2 - 4ac = (-2)^2 - 4(1)(-6) = 4 + 24 = 28$. Since 28 is positive, the equation has two different real-number solutions.

Consider Only the Discriminant b2−4acb ^ { 2 } - 4 a cb2−4ac

Consider Only the Discriminant $b ^ { 2 } - 4 a c$