Consider only the discriminant, $\mathrm { b } ^ { 2 }$ 4ac, to determine whether one real-number solution, two different real-
solutions, or two different imaginary-number solutions exist.
-$$x ^ { 2 } + 10 x + 25 = 0$$
A) Two different real-number solutions
B) Two different imaginary-number solutions
C) One real solution

Question

Quizplus · Accepted Answer

The discriminant is calculated as $b^2 - 4ac$. For the given equation, $a = 1$, $b = 10$, and $c = 25$. Thus, the discriminant is $10^2 - 4(1)(25) = 100 - 100 = 0$. A discriminant of 0 indicates that there is exactly one real solution.

Consider Only the Discriminant b2\mathrm { b } ^ { 2 }b2

Consider Only the Discriminant $\mathrm { b } ^ { 2 }$