Solve the problem.
-In September 1998 the population of the country of West Goma in millions was modeled by $\mathrm { f } ( \mathrm { x } ) = 16.6 \mathrm { e } ^ { 0.0012 \mathrm { x } }$. At the same time the population of East Goma in millions was modeled by $\mathrm { g } ( \mathrm { x } ) = 13.4 \mathrm { e } ^ { 0.0133 \mathrm { x } }$. In both formulas $\mathrm { x }$ is the year, where $\mathrm { x } = 0$ corresponds to September $1998 .$ Assuming these trends continue, estimate the year when the population of West Goma will equal the population of East Goma.
A) 1980
B) 18
C) 2013
D) 2016

Question

Quizplus · Accepted Answer

To find when the populations are equal, set $16.6 e^{0.0012x} = 13.4 e^{0.0133x}$. Solving for $x$ gives approximately 18 years after 1998, which is 2016.

Solve the Problem f(x)=16.6e0.0012x\mathrm { f } ( \mathrm { x } ) = 16.6 \mathrm { e } ^ { 0.0012 \mathrm { x } }f(x)=16.6e0.0012x

Solve the Problem $\mathrm { f } ( \mathrm { x } ) = 16.6 \mathrm { e } ^ { 0.0012 \mathrm { x } }$