A ball rolls across a floor with an acceleration of 0.10 m/s² in a direction opposite to its velocity. The ball has a velocity of 4.00 m/s after rolling a distance 6.00 m across the floor. What was the initial speed of the ball? A)4.15 m/s B)5.85 m/s C)4.60 m/s D)5.21 m/s E)3.85 m/s

Question

Quizplus · Accepted Answer

The correct answer is A because the initial speed of the ball can be calculated using the equation of motion: v^2 = u^2 + 2as, where v is the final velocity, u is the initial velocity, a is the acceleration, and s is the distance traveled. Substituting the given values into the equation, we get: 4.00^2 = u^2 + 2(-0.10)(6.00). Solving for u, we get: u = 4.15 m/s.

A Ball Rolls Across a Floor with an Acceleration of 0.10