Solve.
-A rotating beacon is located a distance $\mathrm { d }$ from a long wall. The distance $\mathrm { d }$ is given by $\mathrm { d } = 2 \tan 2 \pi \mathrm { t }$, where $t$ is the time measured in seconds since the beacon started rotating. Solve the equation for $\mathrm { t }$.
A) $t = 2 \pi \tan \frac { d } { 2 }$
B) $t = \frac { 1 } { 2 \pi } \arctan \frac { \mathrm { d } } { 2 }$
C) $t = \frac { 1 } { 2 \pi } \tan \frac { d } { 2 }$
D) $t = 2 \pi \arctan \frac { d } { 2 }$

Question

Quizplus · Accepted Answer

To solve for $t$, we start with the given equation $d = 2 \tan(2 \pi t)$. We isolate $t$ by applying the inverse tangent ($\arctan$) to both sides and then dividing by $2\pi$, resulting in $t = \frac{1}{2\pi} \arctan\left(\frac{d}{2}\right)$.

Solve -A Rotating Beacon Is Located a Distance d\mathrm { d }d

Solve
-A Rotating Beacon Is Located a Distance $\mathrm { d }$