A mountain search and rescue team receives an average of µ = 0.75 calls per day. Find the probability that on a randomly selected day, they will receive fewer than two calls.
A)0.8266
B)0.3543
C)0.1329
D)0.1734

Question

Quizplus · Accepted Answer

The number of calls per day can be modeled by a Poisson distribution with a mean (µ) of 0.75 calls per day. The probability of receiving fewer than two calls (0 or 1 call) is calculated using the Poisson probability formula: P(X < 2) = P(0) + P(1). P(0) = e^(-0.75) * 0.75^0 / 0! and P(1) = e^(-0.75) * 0.75^1 / 1!. Adding P(0) and P(1) gives the probability of receiving fewer than two calls, which is approximately 0.8266.

A Mountain Search and Rescue Team Receives an Average of µ