A stretched string is observed to have four equal segments in a standing wave driven at a frequency of 480 Hz. What driving frequency will set up a standing wave with five equal
Segments?
A) 120 Hz
B) 240 Hz
C) 600 Hz
D) 360 Hz

Question

Quizplus · Accepted Answer

The frequency required to set up a standing wave with a certain number of segments (or antinodes) is directly proportional to the number of segments. If 4 segments correspond to 480 Hz, then 5 segments, which is 1.25 times more segments, will require 1.25 times the frequency, which is 480 Hz * 1.25 = 600 Hz.

A Stretched String Is Observed to Have Four Equal Segments