In a two-slit experiment using coherent light, the distance between the slits and the screen is $1.10$ $\mathrm { m }$, and the distance between the slits is $0.100 \mathrm {~mm}$. If the first-order bright fringe is measured to be $3.40 \mathrm {~cm}$ from the centerline, what is the wavelength of the light?
A) $3.09 \mu \mathrm { m }$
B) $133 \mathrm {~nm}$
C) $241 \mathrm {~nm}$
D) $354 \mathrm {~nm}$
E) $2.11 \mu \mathrm { m }$

Question

Quizplus · Accepted Answer

The distance between the first-order bright fringe and the centerline is given by:$$y = \frac{\lambda D}{d}$$where $y$ is the distance between the bright fringe and the centerline, $\lambda$ is the wavelength of the light, $D$ is the distance between the slits and the screen, and $d$ is the distance between the slits.Solving for $\lambda$, we get:$$\lambda = \frac{yd}{D}$$Substituting the given values, we get:$$\lambda = \frac{(0.0340 \mathrm {~m})(1.00 \times 10^{-3} \mathrm {~m})}{1.10 \mathrm {~m}} = 3.09 \times 10^{-6} \mathrm {~m} = 3.09 \mu \mathrm { m }$$Therefore, the correct answer is A.

In a Two-Slit Experiment Using Coherent Light, the Distance Between 1.101.101.10

In a Two-Slit Experiment Using Coherent Light, the Distance Between $1.10$