What is the surface temperature of a star, if its radiation peak occurs at a frequency of $1.06 \times 10^{15}$ $\mathrm { Hz }$ ? $\left( c = 3.00 \times 10 ^ { 8 } \mathrm {~m} / \mathrm { s } \right.$, and the constant in Wien's law is $\left. 0.00290 \mathrm {~m} \cdot \mathrm { K } \right)$
A) $17,000 \mathrm {~K}$
B) $14,500 \mathrm {~K}$
C) $10,200 \mathrm {~K}$
D) $20,400 \mathrm {~K}$
E) $19,000 \mathrm {~K}$

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The Answer of What is the surface temperature of a star, if its radiation peak occurs at a frequency of $1.06 \times 10^{15}$ $\mathrm { Hz }$ ? $\left( c = 3.00 \times 10 ^ { 8 } \mathrm {~m} / \mathrm { s } \right.$, and the constant in Wien's law is $\left. 0.00290 \mathrm {~m} \cdot \mathrm { K } \right)$
A) $17,000 \mathrm {~K}$
B) $14,500 \mathrm {~K}$
C) $10,200 \mathrm {~K}$
D) $20,400 \mathrm {~K}$
E) $19,000 \mathrm {~K}$

What Is the Surface Temperature of a Star, If Its 1.06×10151.06 \times 10^{15}1.06×1015

What Is the Surface Temperature of a Star, If Its $1.06 \times 10^{15}$