Here Is the Corresponding Regression Table: Dependent Variable Is: JanTemp $= 71.9 \% \quad$

Here is the corresponding regression table: Dependent variable is: JanTemp
R squared $= 71.9 \% \quad$ R squared (adjusted) $= 71.3 \%$
$\mathrm { s } = 7.222$ with $55 - 2 = 53$ degrees of freedom
$\begin{array} { l l l l l } \text { Source } & \text { Sum of Squares } & \text { df } & \text { Mean Square } & \text { F-ratio } \\ \text { Regression } & 7061.32 & 1 & 7061.32 & 135 \\ \text { Residual } & 2764.21 & 53 & 52.1549 & \\ & & & & \\ \text { Variable } & \text { Coefficient } & \text { SE(Coeff) } & \text { t-ratio } & \text { P-value } \\ \text { Intercept } & 108.805 & 7.146 & 15.2 & \leq 0.0001 \\ \text { Lat } & - 2.11114 & 0.1814 & - 11.6 & \leq 0.0001 \end{array}$
Write a brief report based on this regression. Explain in words and numbers what this
equation says about the relationship between average January low temperature and
latitude. Discuss the R2 value and t-ratios.