$$\begin{array}{l}
\text { Find the mean of the distribution shown. }\
\begin{array} { l | c c }
\boldsymbol { X } & 4 & 6 \
\hline \boldsymbol { P } ( \boldsymbol { X } ) & 0.47 & 0.53
\end{array}
\end{array}$$
A) 1.53
B) 5.06
C) 6.00
D) 4.00

Question

$$\begin{array}{l}
\text { Find the mean of the distribution shown. }\
\begin{array} { l | c c } 
\boldsymbol { X } & 4 & 6 \
\hline \boldsymbol { P } ( \boldsymbol { X } ) & 0.47 & 0.53
\end{array}
\end{array}$$
A) 1.53
B) 5.06
C) 6.00
D) 4.00

Quizplus · Accepted Answer

The mean of a distribution is calculated by summing the products of each value of X and its corresponding probability P(X). Here, it is (4 * 0.47) + (6 * 0.53) = 1.88 + 3.18 = 5.06.

A) 153 B) 5

A) 153
B) 5