Factor completely using the difference of squares along with factoring by grouping. $9 x ^ { 3 } + 7 x ^ { 2 } - 36 x - 28$
A) $( 9 x - 7 ) ( x + 2 ) ( x - 2 )$
B) $( 9 x - 7 ) ( x - 2 ) ^ { 2 }$
C) $( 9 x + 7 ) ( x - 2 ) ^ { 2 }$
D) $( 9 x + 7 ) ( x + 2 ) ( x - 2 )$

Question

Quizplus · Accepted Answer

The Answer of Factor completely using the difference of squares along with factoring by grouping. $9 x ^ { 3 } + 7 x ^ { 2 } - 36 x - 28$
A) $( 9 x - 7 ) ( x + 2 ) ( x - 2 )$
B) $( 9 x - 7 ) ( x - 2 ) ^ { 2 }$
C) $( 9 x + 7 ) ( x - 2 ) ^ { 2 }$
D) $( 9 x + 7 ) ( x + 2 ) ( x - 2 )$

Factor Completely Using the Difference of Squares Along with Factoring 9x3+7x2−36x−289 x ^ { 3 } + 7 x ^ { 2 } - 36 x - 289x3+7x2−36x−28

Factor Completely Using the Difference of Squares Along with Factoring $9 x ^ { 3 } + 7 x ^ { 2 } - 36 x - 28$