Write the equation in exponential form. $\log _ { 17 / 5 } 1 = 0$
A) $\left( \frac { 17 } { 5 } \right) ^ { 0 } = 1$
B) $\frac { 17 ^ { 1 } } { 5 } = 0$
C) $1 ^ { 0 } = \frac { 17 } { 5 }$
D) $\frac { 17 ^ { 0 } } { 5 } = 1$

Question

Quizplus · Accepted Answer

The exponential form of $\log _ { b } a = c$ is $b^c = a$. Here, $b = \frac{17}{5}$, $a = 1$, and $c = 0$, so the correct transformation is $\left( \frac { 17 } { 5 } \right) ^ { 0 } = 1$.

Write the Equation in Exponential Form log⁡17/51=0\log _ { 17 / 5 } 1 = 0log17/5​1=0

Write the Equation in Exponential Form $\log _ { 17 / 5 } 1 = 0$