Solve.
-$$\frac { 4 } { x } + \frac { 4 } { x + 6 } = 1$$
A) 6
B) 4
C) $- 4,6$
D) $4 , - 6$

Question

Quizplus · Accepted Answer

To solve the equation $\frac { 4 } { x } + \frac { 4 } { x + 6 } = 1$, we find a common denominator and solve for $x$. Multiplying both sides by $x(x + 6)$ to eliminate the denominators gives: $4(x + 6) + 4x = x(x + 6)$. Simplifying, we get $4x + 24 + 4x = x^2 + 6x$, leading to $x^2 - 2x - 24 = 0$. Factoring, we find $(x - 6)(x + 4) = 0$, giving the solutions $x = 6$ and $x = -4$.

Solve - 4x+4x+6=1\frac { 4 } { x } + \frac { 4 } { x + 6 } = 1x4​+x+64​=1

Solve
- $\frac { 4 } { x } + \frac { 4 } { x + 6 } = 1$