Find f(x) and g(x) such that h(x) = $(f \circ g)(x)$.
-$$h ( x ) = \frac { 1 } { x ^ { 2 } } + 6$$
A) $f ( x ) = \frac { 1 } { x ^ { 2 } } , g ( x ) = 6$
B) $f ( x ) = \frac { 1 } { x } , g ( x ) = \frac { 1 } { x } + 6$
C) $f ( x ) = x , g ( x ) = \frac { 1 } { x } + 6$
D) $f ( x ) = x + 6 , g ( x ) = \frac { 1 } { x ^ { 2 } }$

Question

Quizplus · Accepted Answer

The correct composition is $f(g(x)) = f\left(\frac{1}{x^2}\right) = \frac{1}{x^2} + 6$, where $f(x) = x + 6$ and $g(x) = \frac{1}{x^2}$.

Find F(x) and G(x) Such That H(x) = (f∘g)(x)(f \circ g)(x)(f∘g)(x)

Find F(x) and G(x) Such That H(x) = $(f \circ g)(x)$