Factor.
-$6 x ^ { 3 } - 26 x ^ { 2 } - 20 x$
A) $2 ( 3 x - 2 ) ( x + 5 )$
B) $x ( 3 x + 2 ) ( 2 x - 10 )$
C) $\left( x ^ { 2 } - 5 \right) ( 6 x + 4 )$
D) $2 x ( 3 x + 2 ) ( x - 5 )$

Question

Quizplus · Accepted Answer

The expression can be factored by first taking out the greatest common factor, which is $2x$, resulting in $2x(3x^2 - 13x - 10)$. Then, factor the quadratic $3x^2 - 13x - 10$ to get $(3x + 2)(x - 5)$. Thus, the complete factorization is $2x(3x + 2)(x - 5)$.

Factor - 6x3−26x2−20x6 x ^ { 3 } - 26 x ^ { 2 } - 20 x6x3−26x2−20x

Factor
- $6 x ^ { 3 } - 26 x ^ { 2 } - 20 x$