Solve.
-The maximum number of volts, E, that can be placed across a resistor is given by the formula $\mathrm { E } = \sqrt { \mathrm { PR } }$, where $\mathrm { P }$ is the number of watts of power that the resistor can absorb and $R$ is the resistance of the resistor in ohms. If a $\frac { 1 } { 4 }$-watt resistor has a resistance of 10,000 ohms, find the largest number of volts of electricity that could be placed across the resistor.
A) 50 volts
B) 25 volts
C) 100 volts
D) 2500 volts

Question

Quizplus · Accepted Answer

The formula $E = \sqrt{PR}$ is used to find the maximum voltage. Substituting $P = \frac{1}{4}$ watt and $R = 10,000$ ohms, we get $E = \sqrt{\frac{1}{4} \times 10,000} = \sqrt{2500} = 50$ volts.

Solve -The Maximum Number of Volts, E, That Can Be E=PR\mathrm { E } = \sqrt { \mathrm { PR } }E=PR​

Solve
-The Maximum Number of Volts, E, That Can Be $\mathrm { E } = \sqrt { \mathrm { PR } }$