Solve the system of equations by the substitution method.
-$\left\{ \begin{array} { l }
\frac { 1 } { 6 } x - 2 y = 1 \
x - 12 y = 6
\end{array} \right.$
A) $( 1 , - 6 )$
B) no solution
C) $( 6 , - 1 )$
D) infinite number of solutions

Question

Solve the system of equations by the substitution method.
-$\left\{ \begin{array} { l } 
\frac { 1 } { 6 } x - 2 y = 1 \
x - 12 y = 6
\end{array} \right.$
A) $( 1 , - 6 )$
B) no solution
C) $( 6 , - 1 )$
D) infinite number of solutions

Quizplus · Accepted Answer

The Answer of Solve the system of equations by the substitution method.
-$\left\{ \begin{array} { l } 
\frac { 1 } { 6 } x - 2 y = 1 \
x - 12 y = 6
\end{array} \right.$
A) $( 1 , - 6 )$
B) no solution
C) $( 6 , - 1 )$
D) infinite number of solutions

Solve the System of Equations by the Substitution Method {16x−2y=1x−12y=6\left\{ \begin{array} { l } \frac { 1 } { 6 } x - 2 y = 1 \\x - 12 y = 6\end{array} \right.{61​x−2y=1x−12y=6​

Solve the System of Equations by the Substitution Method $\left\{ \begin{array} { l } \frac { 1 } { 6 } x - 2 y = 1 \\x - 12 y = 6\end{array} \right.$