Factor the trinomial completely. If the polynomial cannot be factored, write "prime."
-$\mathrm { x } ^ { 2 } ( \mathrm { y } - 2 ) - 9 \mathrm { x } ( \mathrm { y } - 2 ) + 20 ( \mathrm { y } - 2 )$
A) $( x - 4 ) ( x + 5 ) ( y - 2 )$
B) $( x + 4 ) ( x + 5 ) ( y - 2 )$
C) $( x + 4 ) ( x - 5 ) ( y - 2 )$
D) $( x - 4 ) ( x - 5 ) ( y - 2 )$

Question

Quizplus · Accepted Answer

The expression can be factored by first factoring out the common term $(y - 2)$, resulting in $(y - 2)(x^2 - 9x + 20)$. The quadratic $x^2 - 9x + 20$ can be factored into $(x - 4)(x - 5)$.

Factor the Trinomial Completely x2(y−2)−9x(y−2)+20(y−2)\mathrm { x } ^ { 2 } ( \mathrm { y } - 2 ) - 9 \mathrm { x } ( \mathrm { y } - 2 ) + 20 ( \mathrm { y } - 2 )x2(y−2)−9x(y−2)+20(y−2)

Factor the Trinomial Completely $\mathrm { x } ^ { 2 } ( \mathrm { y } - 2 ) - 9 \mathrm { x } ( \mathrm { y } - 2 ) + 20 ( \mathrm { y } - 2 )$