Factor by any method.
-$192 \mathrm { k } ^ { 3 } \mathrm {~m} - 375 \mathrm {~m} ^ { 4 }$
A) $3 \mathrm {~m} ( 4 \mathrm { k } - 5 \mathrm {~m} ) \left( 16 \mathrm { k } ^ { 2 } + 20 \mathrm {~km} + 25 \mathrm {~m} ^ { 2 } \right)$
B) $3 m ( 64 k - 5 m ) \left( k ^ { 2 } + 20 k m + 25 m ^ { 2 } \right)$
C) $\left( 12 k m - 15 m ^ { 2 } \right) \left( 16 k ^ { 2 } + 25 m ^ { 2 } \right)$
D) $3 m \left( 4 k + 5 m ^ { 2 } \right) \left( 16 k ^ { 2 } - 20 k m + 25 k ^ { 2 } \right)$

Question

Quizplus · Accepted Answer

The greatest common factor (GCF) of $192k^3m$ and $375m^4$ is $3m$, leaving us with $64k^3 - 125m^3$ inside the parentheses. This is a difference of cubes, which factors into $(4k - 5m)(16k^2 + 20km + 25m^2)$.

Factor by Any Method 192k3 m−375 m4192 \mathrm { k } ^ { 3 } \mathrm {~m} - 375 \mathrm {~m} ^ { 4 }192k3 m−375 m4

Factor by Any Method $192 \mathrm { k } ^ { 3 } \mathrm {~m} - 375 \mathrm {~m} ^ { 4 }$