Consider the function h as defined. Find functions f and g so that (f ∘ g)(x) = h(x).
-$$h ( x ) = \frac { 1 } { x ^ { 2 } - 7 }$$
A) $f ( x ) = \frac { 1 } { x ^ { 2 } } , g ( x ) = - \frac { 1 } { 7 }$
B) $f ( x ) = \frac { 1 } { x ^ { 2 } } , g ( x ) = x - 7$
C) $f ( x ) = \frac { 1 } { x } , g ( x ) = x ^ { 2 } - 7$
D) $f ( x ) = \frac { 1 } { 7 } , g ( x ) = x ^ { 2 } - 7$

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The Answer of Consider the function h as defined. Find functions f and g so that (f ∘ g)(x) = h(x).
-$$h ( x ) = \frac { 1 } { x ^ { 2 } - 7 }$$
A) $f ( x ) = \frac { 1 } { x ^ { 2 } } , g ( x ) = - \frac { 1 } { 7 }$
B) $f ( x ) = \frac { 1 } { x ^ { 2 } } , g ( x ) = x - 7$
C) $f ( x ) = \frac { 1 } { x } , g ( x ) = x ^ { 2 } - 7$
D) $f ( x ) = \frac { 1 } { 7 } , g ( x ) = x ^ { 2 } - 7$

Consider the Function H as Defined h(x)=1x2−7h ( x ) = \frac { 1 } { x ^ { 2 } - 7 }h(x)=x2−71​

Consider the Function H as Defined $h ( x ) = \frac { 1 } { x ^ { 2 } - 7 }$