For the points P and Q, find the distance d(P, Q).
-$\mathrm { P } ( 3 , - 6 ) , \mathrm { Q } ( 7 , - 4 )$
A) 12
B) $2 \sqrt { 5 }$
C) 2
D) $12 \sqrt { 3 }$

Question

Quizplus · Accepted Answer

The distance between two points $(x_1, y_1)$ and $(x_2, y_2)$ in a plane is given by the formula $d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$. Applying this formula to points P(3, -6) and Q(7, -4), we get $d = \sqrt{(7 - 3)^2 + (-4 + 6)^2} = \sqrt{4^2 + 2^2} = \sqrt{16 + 4} = \sqrt{20} = 2\sqrt{5}$.

For the Points P and Q, Find the Distance D(P P(3,−6),Q(7,−4)\mathrm { P } ( 3 , - 6 ) , \mathrm { Q } ( 7 , - 4 )P(3,−6),Q(7,−4)

For the Points P and Q, Find the Distance D(P $\mathrm { P } ( 3 , - 6 ) , \mathrm { Q } ( 7 , - 4 )$