Solve for the indicated variable.
-$\log _ { s } ( z + y ) = \log _ { s } ( 2 z - 4 ) , \quad$ for $y$
A) $y = \frac { \log _ { \mathrm { s } } \mathrm { z } } { 4 }$
B) $y = \log _ { S } ( z - 4 )$
C) $\mathrm { y } = \mathrm { z } - 4$
D) $y = \frac { z } { 4 }$

Question

Quizplus · Accepted Answer

Given $\log _ { s } ( z + y ) = \log _ { s } ( 2 z - 4 )$, the properties of logarithms allow us to equate the arguments when the bases are the same, leading to $z + y = 2z - 4$. Solving for $y$ gives $y = z - 4$.

Solve for the Indicated Variable log⁡s(z+y)=log⁡s(2z−4),\log _ { s } ( z + y ) = \log _ { s } ( 2 z - 4 ) , \quadlogs​(z+y)=logs​(2z−4),

Solve for the Indicated Variable $\log _ { s } ( z + y ) = \log _ { s } ( 2 z - 4 ) , \quad$