Solve the problem. Round your answer to the nearest tenth, when appropriate. Use the formula $$\mathrm { pH } = - \log \left[ \mathrm { H } _ { 3 } \mathrm { O } ^ { + } \right]$$ as needed.
-Find $\left[ \mathrm { H } _ { 3 } \mathrm { O } ^ { + } \right]$if the $\mathrm { pH } = 1.4$.
A) $4.0 \times 10 ^ { - 2 }$
B) $2.5 \times 10 ^ { - 1 }$
C) $4.0 \times 10 ^ { - 1 }$
D) $2.5 \times 10 ^ { - 2 }$

Question

Quizplus · Accepted Answer

To find $\left[ \mathrm { H } _ { 3 } \mathrm { O } ^ { + } \right]$ given $\mathrm { pH } = 1.4$, use the formula $\mathrm { pH } = - \log \left[ \mathrm { H } _ { 3 } \mathrm { O } ^ { + } \right]$. Rearranging gives $\left[ \mathrm { H } _ { 3 } \mathrm { O } ^ { + } \right] = 10^{-\mathrm{pH}} = 10^{-1.4} = 4.0 \times 10 ^ { - 2 }$.

Solve the Problem pH=−log⁡[H3O+]\mathrm { pH } = - \log \left[ \mathrm { H } _ { 3 } \mathrm { O } ^ { + } \right]pH=−log[H3​O+]

Solve the Problem $\mathrm { pH } = - \log \left[ \mathrm { H } _ { 3 } \mathrm { O } ^ { + } \right]$