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Question 264
Determine the equation of the graph.-
A) y=−sec2xy = - \sec 2 xy=−sec2x B) y=sec(12x) y = \sec \left( \frac { 1 } { 2 } x \right) y=sec(21x) C) y=sec2xy = \sec 2 xy=sec2x D) y=−sec(12x) y = - \sec \left( \frac { 1 } { 2 } x \right) y=−sec(21x)
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