Solve the problem.
-A wheel is rotating at 3 radians/sec, and the wheel has a 44 -inch diameter. To the nearest foot, what is the speed of a point on the rim in $\mathrm { ft } / \mathrm { min }$ ?
A) $330 \mathrm { ft } / \mathrm { min }$
B) $325 \mathrm { ft } / \mathrm { min }$
C) $320 \mathrm { ft } / \mathrm { min }$
D) $335 \mathrm { ft } / \mathrm { min }$

Question

Quizplus · Accepted Answer

The speed of a point on the rim is given by the formula $v = r\omega$, where $v$ is the linear speed, $r$ is the radius of the wheel, and $\omega$ is the angular speed. Here, $r = 22$ inches (half of the diameter) and $\omega = 3$ radians/sec. Converting inches to feet ($22$ inches $= \frac{22}{12}$ feet) and seconds to minutes ($3$ radians/sec $= 3 \times 60$ radians/min), the speed $v = \frac{22}{12} \times 3 \times 60$ feet/min. Simplifying gives $v = 330$ feet/min.

Solve the Problem ft/min\mathrm { ft } / \mathrm { min }ft/min

Solve the Problem $\mathrm { ft } / \mathrm { min }$