Rewrite the following as a product of trigonometric functions.
-$\sin 9 + \sin 32$
A) $2 \sin 20.5 \sin ( - 11.5 )$
B) $2 \cos 20.5 \sin ( - 11.5 )$
C) $2 \cos 20.5 \cos ( - 11.5 )$
D) $2 \sin 20.5 \cos ( - 11.5 )$

Question

Quizplus · Accepted Answer

This can be solved using the sum-to-product identities for sine, which states that $\sin A + \sin B = 2 \sin \left(\frac{A + B}{2}\right) \cos \left(\frac{A - B}{2}\right)$. Applying this to $\sin 9 + \sin 32$, we get $2 \sin \left(\frac{9 + 32}{2}\right) \cos \left(\frac{9 - 32}{2}\right)$, which simplifies to $2 \sin 20.5 \cos (-11.5)$.

Rewrite the Following as a Product of Trigonometric Functions sin⁡9+sin⁡32\sin 9 + \sin 32sin9+sin32

Rewrite the Following as a Product of Trigonometric Functions $\sin 9 + \sin 32$