Rewrite the following as a product of trigonometric functions.
-$$\sin \frac { \pi } { 13 } + \sin \frac { \pi } { 2 }$$
A) $2 \cos \frac { 15 \pi } { 52 } \cos \frac { 11 \pi } { 52 }$
B) $2 \sin \frac { 15 \pi } { 52 } \cos \frac { 11 \pi } { 52 }$
C) $2 \sin \frac { 15 \pi } { 52 } \sin \frac { 11 \pi } { 52 }$
D) $2 \cos \frac { 15 \pi } { 52 } \sin \frac { 11 \pi } { 52 }$

Question

Quizplus · Accepted Answer

The sum-to-product identity for sine functions is used: $\sin A + \sin B = 2 \sin \left( \frac{A+B}{2} \right) \cos \left( \frac{A-B}{2} \right)$. Here, $A = \frac{\pi}{13}$ and $B = \frac{\pi}{2}$.

Rewrite the Following as a Product of Trigonometric Functions sin⁡π13+sin⁡π2\sin \frac { \pi } { 13 } + \sin \frac { \pi } { 2 }sin13π​+sin2π​

Rewrite the Following as a Product of Trigonometric Functions $\sin \frac { \pi } { 13 } + \sin \frac { \pi } { 2 }$