Solve the problem.
-A projectile is fired with an initial velocity of 450 feet per second at an angle of $$70 ^ { \circ }$$ with the horizontal. In how many seconds will the projectile strike the ground? (Round your answer to the
Nearest tenth of a second.)
A) 26.4 sec
B) 30.5 sec
C) 23 sec
D) 29.2 sec

Question

Quizplus · Accepted Answer

The time of flight for a projectile launched at an angle $\theta$ with the horizontal and with an initial velocity $v_0$ is given by the formula $T = \frac{2v_0 \sin(\theta)}{g}$, where $g$ is the acceleration due to gravity (approximately $32 \, \text{ft/s}^2$ on the surface of the Earth). Plugging in the given values: $v_0 = 450 \, \text{ft/s}$ and $\theta = 70^\circ$, we get $T = \frac{2 \times 450 \times \sin(70^\circ)}{32}$. Calculating this gives a time of flight of approximately 26.4 seconds, when rounded to the nearest tenth.

Solve the Problem 70∘70 ^ { \circ }70∘ With the Horizontal

Solve the Problem $70 ^ { \circ }$ With the Horizontal